[DoubleDeuce]

I have the math aptitude of a 10 year old. Could someone please explain the math formula to calculate the probability of opponents holding certain cards. Specifically I'm looking for: if I hold a pocket pair what are the odds that someone holds one of my hole cards?

Any help would be appreciated.

[hachkc]

Assuming Hold'em

Pre flop (2 in 50 = 4%)
Flop (2 in 47 = 4.25%)
Turn (2 in 46 = 4.35%)
River (2 in 45 = 4.44%)

Obviously, this assumes none of your cards are on the board.

[jldecarlo]

Originally Posted by DoubleDeuce

I have the math aptitude of a 10 year old. Could someone please explain the math formula to calculate the probability of opponents holding certain cards. Specifically I'm looking for: if I hold a pocket pair what are the odds that someone holds one of my hole cards?

Any help would be appreciated.

I think you need to phrase the question better.

First of all, the answer to the question as stated is 0%. You have your hole cards. The odds that someone else will have one of the same cards is nill. (smart *ss answer)

Do you want to know the liklihood that a specific person has one (or more) of same value, or that any player has one of the same value. That depends on how many players there are.

Specific player = 1 - (48/50)*(47/49) = 7.9%

You calculate the chances that the other player's first hole card isn't the same value * the chance that the second card also isn't. This gives the chances that the player doesn't hold at least one of your cards. Subtract this from one to give the chances that he does.

L