[JM]

Ok, here's a situation that sometimes screws us up in our regular tourneys. It involves what happens when you go from 3 players to heads up in a particular order.

So there's 3 players, lets call them A, B & C. C is on the button, A = SB, B = BB. C goes all in and loses. Now the button moves to A who was just the SB. According to the rule, BB is always opposite the button. But B was just BB, and A was just SB. So does everything now start over from scratch, and A = SB again and B = BB again??

We use the dead button rules when someone goes out, so we do have some hands where there is no SB or there is a dead button, so I want to be consistent with those rules when we get to heads up with this situation. Its happened a couple of times and we just went with the BB opposite the button rule, but is that right in the scenario above?

[ahopen78]

All you need to know is this.

The same person can not be the BB 2 hands in a row.

[Dwight87]

Originally Posted by ahopen78

All you need to know is this.

The same person can not be the BB 2 hands in a row.

Well, what if the BB busts?

I remember it this way:

Of the 2 players left, who ever started out the last hand with the highest blind gets the button and is SB. So,
1. Button busts, BB is SB and button
2. SB busts, BB is SB and button
3. BB busts, SB is SB and button

Hope that helps.

[Lucky Louie]

Here is a chart and grid that explains it:

http://www.homepokertourney.com/button.htm

I made my own copy of the "grid" and keep it in my chip box for reference.

[JM]

Originally Posted by Lucky Louie

Here is a chart and grid that explains it:

http://www.homepokertourney.com/button.htm

I made my own copy of the "grid" and keep it in my chip box for reference.

Thanks Louie, that's perfect!

Originally Posted by Dwight87

Well, what if the BB busts?

I remember it this way:

Of the 2 players left, who ever started out the last hand with the highest blind gets the button and is SB. So,
1. Button busts, BB is SB and button
2. SB busts, BB is SB and button
3. BB busts, SB is SB and button

Hope that helps.

This is a real easy way to remember it, thanks Dwight!

[JM]

Originally Posted by ahopen78

All you need to know is this.

The same person can not be the BB 2 hands in a row.

Not real helpful, doesn't tell me what you have to do to accomplish this. Dead/No BB? No SB? Both SB?

[plz]

Originally Posted by JM

Ok, here's a situation that sometimes screws us up in our regular tourneys. It involves what happens when you go from 3 players to heads up in a particular order.

So there's 3 players, lets call them A, B & C. C is on the button, A = SB, B = BB. C goes all in and loses. Now the button moves to A who was just the SB. According to the rule, BB is always opposite the button. But B was just BB, and A was just SB. So does everything now start over from scratch, and A = SB again and B = BB again??

We use the dead button rules when someone goes out, so we do have some hands where there is no SB or there is a dead button, so I want to be consistent with those rules when we get to heads up with this situation. Its happened a couple of times and we just went with the BB opposite the button rule, but is that right in the scenario above?

Here's an answer from a friend of mine who is very knowledgeable about tournament play:

"I believe the rule is this: The button (and SB) goes to whoever paid the BB last. In your example, B would get the button, and have the SB on the first heads up hand.

In heads up play, the SB is on the button, and acts first pre-flop, and acts second on the other three betting rounds."

[ahopen78]

Originally Posted by plz

Here's an answer from a friend of mine who is very knowledgeable about tournament play:

"I believe the rule is this: The button (and SB) goes to whoever paid the BB last. In your example, B would get the button, and have the SB on the first heads up hand.

In heads up play, the SB is on the button, and acts first pre-flop, and acts second on the other three betting rounds."

This is exactly what I said, in not so many words: The same person can not be the BB 2 hands in a row.

Meaning, if you just paid the BB, now you get the button and the SB.

If the button busts you would be inclined to pass the button to the player who WAS the SB, but if you do this the BB from last hand is the BB again. so the BB from last hand gets the button and the new SB.

If the the SB busts out, the button passes to the previous BB who now has the button and the SB.

If the BB busts out the button passes to the previous SB and he is the SB again.

In short, just remember PASS the button as usual, but if the passed button makes the BB be same as the previous BB, give him the button.

My apologies for my original short reply.

"Pass the dutchie pa da left hand side"

[Captn_All_In]

Originally Posted by ahopen78

"Pass the dutchie pa da left hand side"

I am not sure why I felt the uncontrollable urge to get up and dance after reading this......and why did I reread, and then sing as I was rereading it????

I need help.

[danopoker]

Button goes to the player who posted the biggest blind -- that sounds right to me. In general this means the button effectively moves counter-clockwise and then alternates as usual.

I would add that if neither remaining player had posted a blind (for instance, if there were four or more players in the previous hand and all but two got knocked out) then it makes sense to me that the button goes to the player who had the earliest position.