[21player]

Cash game
$.50/$1 NL (buyin $100)
10 players
Chips: $.50, $1, $5, $25 and $100
Total number of chips: 500
Amount of each chip should be divisible by 20

Any recommendations?

Thanks,
21player

[Strange]

You'll need very few of the .50 chips, I'd say 50 would be plenty, if it needs to be divisible by 20, then go for 40.

Lots of $1 chips maybe as many as 300. Then 100 $5 and the rest in $25. that would make:

40/300/100/60

You could vary it a bit, to something like

40/340/80/40

At this level you probably won't need $100 chips, but i guess you could do:

40/320/80/40/20

if you really wanted to.

[CaptLego]

Originally Posted by 21player

Cash game
$.50/$1 NL (buyin $100)
10 players
Chips: $.50, $1, $5, $25 and $100
Total number of chips: 500
Amount of each chip should be divisible by 20

Any recommendations?

Thanks,
21player

So far, I like this breakdown:
60 x $.50
180 x $1
180 x $5
80 x $25
----------------
total 500 chips

If you like lots of starting chips, start each player with:
6 x $.50
17 x $1
16 x $5
---------------
39 chips, $100

Use the $25 chips for rebuys, and you'll have enough chips for 20 rebuys.

Since the $.50 chip is only used for SB or completing, six per player seems like enough to go several rounds without needing to make change. You might consider going with a $.25 chip instead, since it would make the set more versatile (and with a 500 chip set, you've got plenty of maneuvering room). If you do go with a $.25 chip, though, you'll want more than 60 of them.


If you want to start with fewer chips/player, use a $25 chip, and adjust the quantities of the others downward.

I don't see any use for a $100 chip here.

[CaptLego]

Originally Posted by Strange

You could vary it a bit, to something like

40/340/80/40

I took a look at this variation....
In general, I think Strange's approach would certainly play better in a limit game, since it has lots and lots of 1's. With this particular breakdown, though, there's not a lot of total $$ in chips, so you'd be limited to 7 rebuys, for example.

40/340/80/40
Starting stacks:
4 x $.50
33 x $1
8 x $5
1 x $25
------------------
46 chips, $100

With ten players, that would leave 30 $25 chips (and 10 x $1) availabe for rebuys.

I guess it depends on the style of your games...

[Matthew]

All good recommendations - another to consider and I only say this from experience - I did a $.50 chip but just need to go to Kinkos to print the labels to make it a $.25. We added in some different games once ina while like 5 Draw and 7 stud which needed an ante.

Also consider having a chip with no denom - which could be worth the $.25 or the $.50 and have the denoms on the rest of the chips.

I would go

100 x $0.25 = $25
200 x $1 = $200
140 x $5 = $700
60 x $25 = $1500

Total = $2425 in cash

If you need more $$$ drop the $0.25 down to 80 chips and bump up the $25 to 80 chips (now $2920 in cash) or add in 20 chips worth $100 (now $4420 in cash).

Matthew

[coyote]

60 x .50 = $30
170 x 1.00 = $170
220 x 5.00 = $1100
50 x 25.00 = $1250

100 buyin:
6 x .50 = 3
17 x 1.00 = 17
11 x 5.00 = 55
1 x 25.00 = 25

leaves you at least 11 full rebuys using 5's and 25's

[Strange]

Having seen Capt Lego's suggestion, I'd probably change mine a little. I like a lot of chips, and I don't get that many rebuys in a game, so i don't need 1000's of $$$
in value.

Maybe reduce the number of $1 and up the number of $5 a little....