[OutOfCrown]

Originally Posted by bjjensen

Well, in this case it's only 1326:1, since he didn't care what the first hand was, only that it was repeated on the second hand. If he had wanted two black 9's on two hands, then the math is accurate.

Correct, for one player. Since there are multiple players at the table, and presumably we were going to be wondering about this event if any of them got the exact same hand twice in a row, the chance of this happening somewhere at the table is far better than 1326:1 (someone else can do that math)